Question

ABCD is a parallelogram. O is the mid point of CD. ΔBOC ≅ ΔEOD by ______.

विकल्प

• SSS

• RHS

• SAS

• ASA

Answer 1

ABCD is a parallelogram. O is the mid point of CD. ΔBOC ≅ ΔEOD by ASA.

Explanation:

To prove that ΔBOC ≅ ΔEOD by ASA:

• BO = EO  ...(Common side)
• ∠BOC = ∠EOD  ...(Vertical angles)
• OC = OD  ...(As O is the midpoint of CD in the parallelogram)

Thus, the two triangles are congruent by the ASA (Angle-Side-Angle) criterion.