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प्रश्न
In ΔABC, PQ || AB, ∠ACD = 150°.
∴ find x.

विकल्प
70°
110°
80°
30°
MCQ
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उत्तर
80°
Explanation:
We use the exterior angle theorem, which states:
The exterior angle of a triangle is equal to the sum of the two interior opposite angles.
In triangle ABC:
∠ACD is an exterior angle given as 150°,
PQ || AB implies that ∠ABC and ∠PQC are alternate interior angles, so they are equal.
Let:
∠ABC = x which is what we need to find,
∠CAB = y.
Then:
∠ACD = ∠ABC + ∠CAB = x + y.
Since ∠ACD = 150°, we have:
x + y = 150°.
Also, since ABC is a triangle:
x + y + ∠ACB = 180°,
So, ∠ACB = 180° – 150°
= 30°
Thus, the required angle x = ∠ABC = 80°.
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