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Question
A toroid of 4000 turns has an outer radius of 26 cm and an inner radius of 25 cm. If the current in the wire is 10 A. Calculate the magnetic field of the toroid.
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Solution
Given:
R1 = 0.25 m;
R2 = 0.26 m;
N = 4000;
i = 10 A
To find: Magnetic field of the toroid (B)
Formula:
B = `mu_0 xx N/l xx i`
where l = mean length of toroid = `2pi((R_1 + R"_2))/2`
Calculation:
From formula,
l = π (R1 + R2)
= π (0.25 + 0.26)
= π × 0.51 m
∴ B = `((4pi xx 10^-7) xx 4000 xx 10)/(pi xx 0.51)`
= `16/0.51 xx 10^-3`
∴ Bin = 3.137 × 10−2 T
The magnetic field of the toroid is 3.137 × 10−2 T.
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