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Karnataka Board PUCPUC Science Class 11

A Steel Rod is Clamped at Its Two Ends and Rests on a Fixed Horizontal Base. the Rod is Unstrained at 20°C.

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Question

A steel rod is clamped at its two ends and rests on a fixed horizontal base. The rod is unstrained at 20°C.
Find the longitudinal strain developed in the rod if the temperature rises to 50°C. Coefficient of linear expansion of steel = 1.2 × 10–5 °C–1.

Answer in Brief
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Solution

Given:
Temperature at which rod is resting on a fixed horizontal base without any strain, T1=20 °C. Then the rod is heated to temperature, T2 = 50 °C

​So change in temperature,ΔT =T2-T1=30°C

Coefficient of linear expansion of steel, α = 1.2 × 10–5 °C-1​ 
Let L be the length of the rod without heating and L' be the length of the rod on heating.
Let longitudinal strain developed in the rod be S.
We know that

L' =L(1+∝ΔT)

⇒ ΔL =L∝ΔT

Strain, S = `(ΔL)/L`

`=(L∝ΔT)/L`

=αΔT

⇒ S =1.2 × 10-5 ×(50-20)

=1.2 × 10-5 ×30

=1.2 × 10-5 × 30

=36 × 10-5 

S = 3.6 × 10-4

The strain of 3.6 × 10-4 will be opposite to the direction of expansion.

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Chapter 23: Heat and Temperature - Exercises [Page 13]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 23 Heat and Temperature
Exercises | Q 27 | Page 13

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