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A solid cuboid of iron with dimensions 53 cm ⨯ 40 cm ⨯ 15 cm is melted and recast into a cylindrical pipe. The outer and inner diameters of pipe are 8 cm and 7 cm respectively. Find the length of pipe - Mathematics

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Question

A solid cuboid of iron with dimensions 53 cm ⨯ 40 cm ⨯ 15 cm is melted and recast into a cylindrical pipe. The outer and inner diameters of pipe are 8 cm and 7 cm respectively. Find the length of pipe.

Sum
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Solution

Given,

The outer and inner diameters of pipe are 8 cm and 7 cm.

Dimensions of a solid cuboid of iron = 53 cm × 40 cm × 15 cm.

When a shape melted and recast into another shape volume will remain same.

Volume of cubical iron = volume of cylindrical pipe

length × breadth × height = π(R2 − r2)h

53 × 40 × 15 = `22/7 xx (4^2 - (7/2)^2)h`

53 × 40 × 15 = `22/7 xx 15/4 xx h`

h = `(53 xx 40 xx 15 xx 7 xx 4)/(22 xx 15)`

h = 2698.18 cm = 27 m [∵ 1 m = 100 cm]

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Chapter 14: Surface Areas and Volumes - Exercise 14.1 [Page 29]

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RD Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
Exercise 14.1 | Q 23 | Page 29

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