English
Karnataka Board PUCPUC Science Class 11

A Small Metal Plate (Work Function φ) is Kept at a Distance D from a Singly-ionised, Fixed Ion. a Monochromatic Light Beam is Incident on the Metal Plate and Photoelectrons Are Emitted.

Advertisements
Advertisements

Question

A small metal plate (work function φ) is kept at a distance d from a singly-ionised, fixed ion. A monochromatic light beam is incident on the metal plate and photoelectrons are emitted. Find the maximum wavelength of the light beam, so that some of the photoelectrons may go round the ion along a circle.

Sum
Advertisements

Solution

From Einstein's photoelectric equation ,

`eV_0 = (hc)/lambda - phi`

⇒ `V_0 = ((hc)/lambda - phi)1/e`

Here, V0 = stopping potential
            h = Planck's constant
            c = speed of light
            `phi ` = work function

The particle will move in a circle when the stopping potential is equal to the potential due to the singly charged ion at that point so that the particle gets the required centripetal force for its circular motion.

`⇒ (Ke)/(2d) = ((hc)/lambda - phi)1/e`

`⇒ (Ke^2)/(2d) = (hc)/lambda - phi`

`⇒ (hc)/lambda = (Ke^2)/(2d) + phi = (Ke^2+2dphi)/(2d)`

`⇒ lambda = ((hc)(2d))/(ke^2+2dphi)`

`⇒ lambda = (2hdc)/(1/(4pi∈_0)e^2+2dphi`

`⇒ lambda = (8pi∈_0hcd)/(e^2+8pi∈_0dphi)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 42: Photoelectric Effect and Wave-Particle Duality - Exercises [Page 366]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 42 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 34 | Page 366

RELATED QUESTIONS

In an experiment on the photoelectric effect, the slope of the cut-off voltage versus the frequency of incident light is found to be 4.12 × 10−15 Vs. Calculate the value of Planck’s constant.


The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?


point out any two characteristic properties of photons on which Einstein’s photoelectric equation is based ?


Briefly explain the three observed features which can be explained by Einstein’s photoelectric equation.


Define the terms (i) ‘cut-off voltage’ and (ii) ‘threshold frequency’ in relation to the phenomenon of photoelectric effect.

Using Einstein’s photoelectric equation shows how the cut-off voltage and threshold frequency for a given photosensitive material can be determined with the help of a suitable plot/graph.


Is p − E/c valid for electrons?


A non-monochromatic light is used in an experiment on photoelectric effect. The stopping potential


The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


A monochromatic light source of intensity 5 mW emits 8 × 1015 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Consider the situation of the previous problem. Consider the faster electron emitted parallel to the large metal plate. Find the displacement of this electron parallel to its initial velocity before it strikes the large metal plate.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


How does one explain the emission of electrons from a photosensitive surface with the help of Einstein’s photoelectric equation? 


Each photon has the same speed but different ______.


The minimum energy required to remove an electron is called ______.


  1. In the explanation of photo electric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as Emax = hν – φ where φ0 is the work function of the metal. If an electron absorbs 2 photons (each of frequency ν) what will be the maximum energy for the emitted electron?
  2. Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential?

Radiation of frequency 1015 Hz is incident on three photosensitive surfaces A, B and C. Following observations are recorded:

Surface A: no photoemission occurs

Surface B: photoemission occurs but the photoelectrons have zero kinetic energy.

Surface C: photo emission occurs and photoelectrons have some kinetic energy.
Using Einstein’s photo-electric equation, explain the three observations.


The photon emitted during the de-excitation from the first excited level to the ground state of a hydrogen atom is used to irradiate a photocathode in which the stopping potential is 5 V. Calculate the work function of the cathode used.


If c is the velocity of light in free space, the correct statements about photon among the following are:

  1. The energy of a photon is E = hv.
  2. The velocity of a photon is c.
  3. The momentum of a photon, ρ = `(h v)/c`.
  4. In a photon-electron collision, both total energy and total momentum are conserved.
  5. Photon possesses positive charge.

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×