English
Karnataka Board PUCPUC Science Class 11

A Small Metal Plate (Work Function φ) is Kept at a Distance D from a Singly-ionised, Fixed Ion. a Monochromatic Light Beam is Incident on the Metal Plate and Photoelectrons Are Emitted.

Advertisements
Advertisements

Question

A small metal plate (work function φ) is kept at a distance d from a singly-ionised, fixed ion. A monochromatic light beam is incident on the metal plate and photoelectrons are emitted. Find the maximum wavelength of the light beam, so that some of the photoelectrons may go round the ion along a circle.

Sum
Advertisements

Solution

From Einstein's photoelectric equation ,

`eV_0 = (hc)/lambda - phi`

⇒ `V_0 = ((hc)/lambda - phi)1/e`

Here, V0 = stopping potential
            h = Planck's constant
            c = speed of light
            `phi ` = work function

The particle will move in a circle when the stopping potential is equal to the potential due to the singly charged ion at that point so that the particle gets the required centripetal force for its circular motion.

`⇒ (Ke)/(2d) = ((hc)/lambda - phi)1/e`

`⇒ (Ke^2)/(2d) = (hc)/lambda - phi`

`⇒ (hc)/lambda = (Ke^2)/(2d) + phi = (Ke^2+2dphi)/(2d)`

`⇒ lambda = ((hc)(2d))/(ke^2+2dphi)`

`⇒ lambda = (2hdc)/(1/(4pi∈_0)e^2+2dphi`

`⇒ lambda = (8pi∈_0hcd)/(e^2+8pi∈_0dphi)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 42: Photoelectric Effect and Wave-Particle Duality - Exercises [Page 366]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 42 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 34 | Page 366

RELATED QUESTIONS

The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?


Write Einstein’s photoelectric equation?


Briefly explain the three observed features which can be explained by Einstein’s photoelectric equation.


The frequency and intensity of a light source are doubled. Consider the following statements.

(A) The saturation photocurrent remains almost the same.
(B) The maximum kinetic energy of the photoelectrons is doubled.


The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


A monochromatic light source of intensity 5 mW emits 8 × 1015 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


In a photoelectric experiment, the collector plate is at 2.0 V with respect to the emitter plate made of copper (φ = 4.5 eV). The emitter is illuminated by a source of monochromatic light of wavelength 200 nm. Find the minimum and maximum kinetic energy of the photoelectrons reaching the collector.


Consider the situation of the previous problem. Consider the faster electron emitted parallel to the large metal plate. Find the displacement of this electron parallel to its initial velocity before it strikes the large metal plate.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


How does one explain the emission of electrons from a photosensitive surface with the help of Einstein’s photoelectric equation? 


Use Einstein's photoelectric equation to show how from this graph,
(i) Threshold frequency, and
(ii) Planck's constant can be determined.


According to Einstein's photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal versus the frequency of the incident radiation gives a straight line, whose slope ______.


The minimum energy required to remove an electron is called ______.


  1. In the explanation of photo electric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as Emax = hν – φ where φ0 is the work function of the metal. If an electron absorbs 2 photons (each of frequency ν) what will be the maximum energy for the emitted electron?
  2. Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential?

A student performs an experiment on photoelectric effect, using two materials A and B. A plot of Vstop vs ν is given in Figure.

  1. Which material A or B has a higher work function?
  2. Given the electric charge of an electron = 1.6 × 10–19 C, find the value of h obtained from the experiment for both A and B.

Comment on whether it is consistent with Einstein’s theory:


Radiation of frequency 1015 Hz is incident on three photosensitive surfaces A, B and C. Following observations are recorded:

Surface A: no photoemission occurs

Surface B: photoemission occurs but the photoelectrons have zero kinetic energy.

Surface C: photo emission occurs and photoelectrons have some kinetic energy.
Using Einstein’s photo-electric equation, explain the three observations.


A photon of wavelength 663 nm is incident on a metal surface. The work function of the metal is 1.50 eV. The maximum kinetic energy of the emitted photoelectrons is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×