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A reaction takes place in two steps: (i) NOA(g)+ClA2A(g)⟶NOClA2A(g) (ii) NOClA2A(g)+NOA(g)⟶2NOClA(g) (a) Write the overall reaction. (b) Identify the reaction intermediate.

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Questions

A reaction takes place in two steps:

  1. \[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl2_{(g)}}\]
  2. \[\ce{NOCl2_{(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]
  1. Write the overall reaction.
  2. Identify the reaction intermediate.
  3. What is the molecularity of each step?

A reaction takes place in two steps:

  1. \[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl2_{(g)}}\]
  2. \[\ce{NOCl2_{(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]
  1. Write the overall reaction.
  2. Identify the reaction intermediate.
Chemical Equations/Structures
Very Short Answer
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Solution

  1. Overall reaction: \[\ce{2NO_{(g)} + Cl_{2(g)} -> 2NOCl_{(g)}}\]
  2. Since NOCl2 is formed in the first step and consumed in the second step, it is the reaction intermediate.
  3. The molecularity of each step is 2 because two reactants are involved in each of the steps.
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Notes

Students should refer to the answer according to their questions.

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Chapter 6: Chemical Kinetics - Exercises [Page 136]

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Balbharati Chemistry [English] Standard 12 Maharashtra State Board
Chapter 6 Chemical Kinetics
Exercises | Q 3. iii. | Page 136
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