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Tamil Nadu Board of Secondary EducationHSC Science Class 12

A random variable X has the following probability mass function. x 1 2 3 4 5 F(x) k2 2k2 3k2 2k 3k Find P(X > 3)

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Question

A random variable X has the following probability mass function.

x 1 2 3 4 5
F(x) k2 2k2 3k2 2k 3k

Find P(X > 3)

Sum
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Solution

P(X > 3) = P(X = 4) + P(X = 5)

= `2/6 + 3/6`

= `5/6`

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Chapter 11: Probability Distributions - Exercise 11.2 [Page 194]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 11 Probability Distributions
Exercise 11.2 | Q 6. (iii) | Page 194

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