Advertisements
Advertisements
Question
A manufacturer of TV sets produces 600 units in the third year and 700 units in the 7th year. Assuming that the production increases uniformly by a fixed number every year, find:
- the production in the first year.
- the production in the 10th year.
- the total production in 7 years.
Advertisements
Solution
Since the production increases uniformly by a fixed number every year, the sequence formed by the production in different years in an A.P.
Let the production in the first year = a
Common difference = number of units by which the production increases every year = d
We have,
t3 = 600
`\implies` a + 2d = 600 ...(1)
t7 = 700
`\implies` a + 6d = 700 ...(2)
Subtracting (1) from (2), we get
4d = 100
`\implies` d = 25
`\implies` a + 2 × 25 = 600
`\implies` a = 550
i. The production in the first year = 550 Tv sets
ii. The production in the 10th year = t10
= 550 + 9 × 25
= 775 Tv sets
iii. The total production in 7 years = S7
= `7/2[2 xx 550 + 6 xx 25]`
= `7/2 [1100 + 150]`
= `7/2 xx 1250`
= 4375 Tv sets
APPEARS IN
RELATED QUESTIONS
Find the sum of first 40 positive integers divisible by 6.
Find the sum of all multiples of 7 lying between 300 and 700.
Find the 8th term from the end of the AP 7, 10, 13, ..., 184.
Find the value of x for which the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.
Choose the correct alternative answer for the following question.
For an given A.P. a = 3.5, d = 0, n = 101, then tn = ....
The Sum of first five multiples of 3 is ______.
Write the value of x for which 2x, x + 10 and 3x + 2 are in A.P.
If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164?
An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three is 429. Find the AP.
Find the sum:
`(a - b)/(a + b) + (3a - 2b)/(a + b) + (5a - 3b)/(a + b) +` ... to 11 terms
