Advertisements
Advertisements
Question
A machine raises a load of 750 N through a height of 16 m in 5s. calculate:
(i) work done by machine,
(ii) power at which the machine works.
Advertisements
Solution
Given, load m = 750 N, displacement h = 16 m, time = 5 s, g = 10 N kg -1
now work done = mgh = 750 x 16 = 12000J
or power = `"work done"/"time taken" = 12000/5` = 2400 watt
APPEARS IN
RELATED QUESTIONS
Fill in the blank with suitable word :
1 joule is the work done when a force of 1 __________ moves an object through a distance of one __________ in the direction of __________.
A boy throws a rubber ball vertically upwards. What type of work, positive or negative, is done : by the force applied by the boy?
(a) by the force applied by the boy?
(b) by the gravitational force of earth?
Name the physical quantity whose SI unit is Nm.
Can work done be zero even if force acts on the body?
Name the physical quantity associated with the 'rate of doing work'.
Fill in the boxe to show the corresponding energy transformation.

Explain, why submarines are able to dive underwater as well as a sail on the surface of the water?
The weights of two bodies are 2.0 N and 2.0 kgf respectively what is the mass of each body?
A ______ should act on an object.
