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Question
A line segment is of length 10 units. If the coordinates of its one end are (2, −3) and the abscissa of the other end is 10, then its ordinate is
Options
9, 6
3, −9
−3, 9
9, −6
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Solution
It is given that distance between P (2,−3) and Q(10 , y) is 10.
In general, the distance between A(x1 , y1) and B(x2 , y2 ) is given by,
`AB^2 = (x_2 - x_1 )^2 + (y_2 - y_1 )^2`
So,
`10^2 = (10 - 2)^2 + (y + 3)^2`
On further simplification,
`(y + 3 )^2 = 36`
`y = -3+-6`
`= -9 , 3`
We will neglect the negative value. So,
` y= -9 , 3`
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