Question

A line segment is of length 10 units. If the coordinates of its one end are (2, −3) and the abscissa of the other end is 10, then its ordinate is

Options

• 9, 6

•  3, −9

•  −3, 9

•  9, −6

Answer 1

It is given that distance between P (2,−3) and Q(10 , y)  is 10.

In general, the distance between A(x₁ , y₁)  and B(x₂ , y₂ ) is given by,

`AB^2 = (x_2 - x_1 )^2 + (y_2 - y_1 )^2`

So,

`10^2 = (10 - 2)^2 + (y + 3)^2`

On further simplification,

  `(y + 3 )^2 = 36`

              `y = -3+-6`

                 `= -9 , 3`

We will neglect the negative value. So,

   ` y= -9 , 3`