Advertisements
Advertisements
Question
A group of labourers promises to do a piece of work in 10 days, but five of them become absent. If the remaining labourers complete the work in 12 days, find their original number in the group.
Advertisements
Solution
Total period = 10 days
But work completed in = 12 days
No. of men was absent = 5
Let the number of men in the beginning = x
Now x men can do piece work in = 10 days
1 man will do it in = 10x × days
and (x − 5) will do it in =`(10xx"x")/("x"-5)` days
∴ `(10"x")/("x"-5)=12`
⇒ 10x = 12x − 60
⇒ 12x − 10x = 60 ⇒ 2x = 60
⇒ x =`60/2` = 30
∴ No. of men in the beginning = 30
APPEARS IN
RELATED QUESTIONS
If `2/9` of property costs Rs.2,52,000; find the cost of `4/7` of it.
A particular work can be completed by 6 men and 6 women in 24 days; whereas the same work can be completed by 8 men and 12 women in 15 days. Find :
(i) according to the amount of work done, one man is equivalent to how many women.
(ii) the time is taken by 4 men and 6 women to complete the same work.
Fifteen men can build a wall in 60 days. How many more men are required to build another wall of the same size in 45 days?
A contractor undertakes to build a wall 1000 m long in 50 days. He employs 56 men, but at the end of 27 days, he finds that only 448 m of wall is built. How many extra men must the contractor employ so that the wall is completed in time?
The price of 25 identical articles is ₹1,750. Find the price of one article
If the cost of a dozen soaps is ₹ 460.80, what will the cost of 15 soaps?
The cost of 35 envelops is ₹ 105. How many envelops can be bought for ₹ 90?
Weight of 15 books is 6 kg. What is the weight of 45 such books?
What is the primary objective of the "Unitary Method"?
In the unitary method, which mathematical operation is used to convert the value of "many" units to the value of "one" unit?
