Advertisements
Advertisements
Question
A ground is in the form of a circle whose diameter is 350 m. An athlete makes 4 revolutions. Find the distance covered by the athlete
Advertisements
Solution
Diameter of the ground d = 350 m
Distance covered in 1 revolution = Circumference of the circle
= πd units
= `22/7 xx 350 "m"`
= 22 × 50
= 1100 m
Distance covered in 1 rotation = 1100 m
Distance covered in 4 revolutions = 1100 × 4
= 4400 m
APPEARS IN
RELATED QUESTIONS
In Fig 4, a circle is inscribed in an equilateral triangle ABC of side 12 cm. Find the radius of inscribed circle and the area of the shaded region.[Use π=3.14 and √3=1.73]
The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days. (Take π = 22/7)
A gardener wants to fence a circular garden of diameter 21 m. Find the length of the rope he needs to purchase, if he makes 2 rounds of fence. Also find the costs of the rope, if it cost ₹ 4 per meter. (Take `pi = 22/7`)
Find the circumference and area of circle of radius 4.2 cm
The area of rhombus is `480cm^2` , and one of its diagonal measures 48 cm. Find
(i) the length of the other diagonal,
(ii) the length of each of the sides
(iii) its perimeter
Find the diameter of the circle whose area is equal to the sum of the areas of two circles having radii 4 cm and 3 cm.
The length of a chain used as the boundary of a semicircular park is 108 m. Find the area of the park.
Construct the circumcircle of the ABC when BC = 6 cm, B = 55° and C = 70°.
The cost of fencing a circular race course at the rate of ₹ 8 per metre is ₹ 2112. Find the diameter of the race course
The perimeter of circular and square fields is equal. If the area of the square field is 484 m2 then the diameter of the circular field is ____________.
