Question

Construct the circumcircle of the ABC when BC = 6 cm, B = 55° and C = 70°.

Answer 1

Steps of construction:
(i) Draw a line segment BC = 6 cm.
(ii) At point B, make ∠ CBA = 55°, and at point C, make an angle ∠ BCA = 70° with the help of a protractor. Join AB and AC.
(iii) Draw the perpendicular bisectors of sides AB and AC. Let them intersects at O.
(iv) With O as centre and radius OA, draw a circle which passes through the point A, B and C. This is the required circumcircle of ΔABC.