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Question
A gas mixture consists of molecules of types A, B and C with masses mA > mB > mC. Rank the three types of molecules in decreasing order of average K.E.
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Solution
The average K.E. will be the same, as conditions of temperature and pressure are the same.
Now as, `v_(rms) = sqrt((3pV)/M) = sqrt((3RT)/M)`
= `sqrt((3RT)/(mN)) = sqrt((3kT)/m)`
Where, M = Molar mass of the gas
m = Mass of each molecular of the gas
R = Gas constant
Clearly, `v_(rms) ∝ sqrt(1/m)`
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