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Question
A die is thrown once. Find the probability of getting a number less than 5.
Short/Brief Note
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Solution
In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Total number of possible outcomes = 6
Let E be the event of getting a number less than 5.
Then, the favourable outcomes are 1, 2, 3, 4
Number of favourable outcomes = 4
∴ Probability of getting a number less than 5 = P (E) = `"Number of favourable outcome"/"Total number of possible outcomes"=4/6 = 2/3`
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