Question

A die is thrown once. Find the probability of getting a number greater than 2.

Answer 1

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting a number greater than 2.

Then, the favourable outcomes are 3, 4, 5 and 6.

Number of favourable outcomes = 4

∴ Probability of getting a number greater than 2 =  P (E) =`"Number of favourable outcomes"/"Total number of possible outcomes" = 4/6 = 2/3`