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A convex polygon has 44 diagonals. Find the number of its sides.

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Question

A convex polygon has 44 diagonals. Find the number of its sides.

Sum
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Solution

Let n be the number of sides in a polygon.

Since, Polygon of n sides has (nC2 – n) number of diagonals

nC2 – n = 44

= `(n!)/(2!(n - 2)!)` – n = 44

= `(n(n - 1)(n - 2)!)/(2*(n - 2)!)` – n = 44

⇒ `(n(n - 1))/2` – n = 44

= `(n^2 - n - 2n)/2` = 44

⇒ n2 – 3n = 44

⇒ n2 – 3n – 88 = 0

= n2 – 11n + 8n – 88 = 0

⇒ n(n – 11) + 8(n – 11) = 0

= (n – 11(n + 8) = 0

∴  n = 11 and n = – 8  ....[∵ n ≠ – 8]

So n = 11

Hence, the required number of sides = 11.

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Chapter 7: Permutations and Combinations - Exercise [Page 123]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 20 | Page 123

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