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Question
88Ra226 experiences three α - decay. Find the number of neutrons in the daughter element.
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Solution
Given: Mass number of 88Ra226 = 226
Atomic number of 88Ra226 = 88
Mass number of α = 4
Atomic number of α = 2
After 3 α decay, Mass number of the daughter element will be,
= 226 − (3 × 4)
= 226 − 12
= 214
Atomic number of daughter element is,
= 88 − (3 × 2)
= 88 − 6
= 82
∴ Number of neutrons = 214 − 82
= 132
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