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प्रश्न
88Ra226 experiences three α - decay. Find the number of neutrons in the daughter element.
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उत्तर
Given: Mass number of 88Ra226 = 226
Atomic number of 88Ra226 = 88
Mass number of α = 4
Atomic number of α = 2
After 3 α decay, Mass number of the daughter element will be,
= 226 − (3 × 4)
= 226 − 12
= 214
Atomic number of daughter element is,
= 88 − (3 × 2)
= 88 − 6
= 82
∴ Number of neutrons = 214 − 82
= 132
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संबंधित प्रश्न
Answer the following questions based on a hot cathode ray tube
Name the charged particles
What are free electrons?
A radioactive substance is oxidized. Will there be any change in the nature its radioactivity? Give a reason for your answer
What happens to the atomic number of element when (i) An α -particle, (ii) A β -particle 1 and (iii) γ-radiation is emitted?
What kind of change takes place in a nucleus when a β -particle is emitted?
Define bound electrons.
In a cathode ray tube state. How is it possible to increase the rate of emission of electrons.
What is the value of the speed of gamma radiations in air or vacuum?
Two radioactive sources A and B of half lives of 1 hour and 2 hours, respectively, initially contain the same number of radioactive atoms. At the end of two hours, their rates of disintegration are in the ratio of ______.
Assertion (A): The force of repulsion between atomic nucleus and α-particle varies with distance according to inverse square law.
Reason (R): Rutherford did α-particles scattering experiment.
