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Question
67.2 litres of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as:
\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]
Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture?
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Solution
According to the equation,
\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]
One mole of nitrogen combines with 3 moles of hydrogen to give 2 moles of ammonia.
∴ 3 × 22.4 litre of hydrogen require = 22.4 L of nitrogen
Since nitrogen is present in excess amounts, it remains the resultant.
Mixture and volume of ammonia produced = 2 × 22.4 L
= 44.8 L
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