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24 g of carbon reacts with some oxygen to make 88 grams of carbon dioxide. Find out how much oxygen must have been used. - Chemistry

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Question

24 g of carbon reacts with some oxygen to make 88 grams of carbon dioxide. Find out how much oxygen must have been used.

Numerical
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Solution

Given: Mass of carbon (reactant) = 24 g, mass of carbon dioxide (product) = 88 g

To find: Mass of oxygen (reactant)

Calculation: 12 g of carbon combines with 32 g of oxygen to form 44 g of carbon dioxide as follows:

\[\ce{\underset{12g}{Carbon} + \underset{32g}{Oxygen} -> \underset{44g}{Carbon dioxide}}\]

Hence, (2 × 12 = 24 g) of carbon will combine with (2 × 32 = 64 g) of oxygen to give (2 × 44 = 88 g) carbon dioxide.

Mass of oxygen used = 64 g

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Chapter 1: Some Basic Concepts of Chemistry - Exercises [Page 12]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 1 Some Basic Concepts of Chemistry
Exercises | Q 4. (J) | Page 12

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