Advertisements
Advertisements
Question
10% of x° is the complement of 40% of 2x°. Find x
Advertisements
Solution
∵ 10% of x° is the complement of 40% of 2x°
∴ 10% of x° + 40% of 2x° = 90°
⇒ `10/100"x"+40/100xx2"x"=90°`
⇒ `(10"x")/100+(80"x")/100=90°`
⇒ `(90"x")/100` = 90°
∴ x = `(90xx100)/90`= 100°
Hence x = 100°
APPEARS IN
RELATED QUESTIONS
Are the following pairs of angles complementary?
37° 28′ and 52° 33′
Are the following pairs of angles complementary?
54° and `2/5` of a right angle.
Are the following pairs of angles supplementary?
2x° + 65° and 115°− 2x°
If two complementary angles are in the ratio 1 : 5, find them.
Use the adjacent figure, to find angle x and its supplement.
In the given figure, find ∠AOB and ∠BOC.
Identify the given pair of angles as ∠3 and ∠6
Identify the given pair of angles as ∠10 and ∠12
Identify the given pair of angles as ∠2 and ∠13
If two angles share a common vertex and one common arm, with their other arms on opposite sides of that common arm, what are they called?
