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Question
In the given figure, find ∠AOB and ∠BOC.
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Solution
In the figure,
5x + x + 80° + 123° + 85° = 360° ....(Angles at a point)
⇒ 6x + 80° + 123° + 85° = 360°
⇒ 6x + 288° = 360°
⇒ 6x = 360°− 288° = 72°
⇒ x = `(72°)/6` = 12°
Now, ∠AOB = 5x = 5 × 12° = 60°
and ∠BOC = x = 12°
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