Advertisements
Advertisements
प्रश्न
10% of x° is the complement of 40% of 2x°. Find x
Advertisements
उत्तर
∵ 10% of x° is the complement of 40% of 2x°
∴ 10% of x° + 40% of 2x° = 90°
⇒ `10/100"x"+40/100xx2"x"=90°`
⇒ `(10"x")/100+(80"x")/100=90°`
⇒ `(90"x")/100` = 90°
∴ x = `(90xx100)/90`= 100°
Hence x = 100°
APPEARS IN
संबंधित प्रश्न
Are the following pairs of angles supplementary?
2x° + 65° and 115°− 2x°
Are the following pairs of angles supplementary?
`3/10` of a right angle and `4/15` of two right angles.
If 3x + 18° and 2x + 25° are supplementary, find the value of x.
If two complementary angles are in the ratio 1 : 5, find them.
Find k of the given figure.

Find each angle shown in the diagram.

Find K in the given figure.
Identify the given pair of angles as ∠3 and ∠7

Identify the given pair of angles as ∠7 and ∠9

The necessary condition for the formation of vertically opposite angles is:
