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SSC (English Medium) इयत्ता १० वी - Maharashtra State Board Question Bank Solutions for Geometry Mathematics 2

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Geometry Mathematics 2
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Find the distance between the following pairs of points:

(−5, 7), (−1, 3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

If `theta = 45^@`, then find `tan theta`.

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

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The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Prove that: If the angles of a triangle are 45° – 45° – 90°, then each of the perpendicular sides is \[\frac{1}{\sqrt{2}}\]times the hypotenuse.”

 

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

In the given figure, AD is the bisector of the exterior ∠A of ∆ABC. Seg AD intersects the side BC produced in D. Prove that:

\[\frac{BD}{CD} = \frac{AB}{AC}\]
[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Construct the circumcircle and incircle of an equilateral ∆XYZ with side 6.5 cm and centre O. Find the ratio of the radii of incircle and circumcircle.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`
[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

 In trapezium PQRS, side PQ || side SR, AR = 5AP, AS = 5AQ then prove that, SR = 5PQ 

 

 

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In trapezium ABCD, side AB || side DC, diagonals AC and BD intersect in point O. If AB = 20, DC = 6, OB = 15 then Find OD. 

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

∆PQR ~ ∆LTR. In ∆PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct ∆PQR and ∆LTR, such that `"PQ"/"LT" = 3/4`.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

∆AMT ~ ∆AHE. In ∆AMT, AM = 6.3 cm, ∠TAM = 50°, AT = 5.6 cm. `"AM"/"AH" = 7/5`. Construct ∆AHE.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

∆ABC ~ ∆LBN. In ∆ABC, AB = 5.1 cm, ∠B = 40°, BC = 4.8 cm, \[\frac{AC}{LN} = \frac{4}{7}\]. Construct ∆ABC and ∆LBN.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

Construct ∆PYQ such that, PY = 6.3 cm, YQ = 7.2 cm, PQ = 5.8 cm. If \[\frac{YZ}{YQ} = \frac{6}{5},\] then construct ∆XYZ similar to ∆PYQ.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

Find the distance between the following pair of point.

 P(–5, 7), Q(–1, 3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of points.

R(0, -3), S(0, `5/2`)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of points.

L(5, –8), M(–7, –3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of point.

T(–3, 6), R(9, –10)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pairs of point.

W `((- 7)/2 , 4)`, X (11, 4)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined
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