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Give the empirical formula of CH3COOH

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Give example of compound whose:
Empirical formula is the same as the molecular formula.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

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Give example of compound whose:
Empirical formula is different from the molecular formula.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place)  (H=1,C=12,O=16)

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:  2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined

Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

When gases react their volumes bear a simple ratio to each other, under the same conditions of temperature and pressure. Who proposed this gas law?

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined

What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined

The reaction 4N2O + CH4 → CO2 + 2H2O + 4N2 takes place in the gaseous state. If the volumes of all the gases are measured at the same temperature, and pressure, calculate the volume of dinitrogen oxide (N2O), required to give 150cm3 of steam.

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined

The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
Determine the empirical formula of this compound.
[C = 12, Br = 80]

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens because of the heat evolved while calcium carbide reacts with the moisture. During this reaction calcium hydroxide and acetylene gas are formed. If 200 cm3 of acetylene is formed from a certain mass of calcium carbide, find the volume of oxygen required and carbon dioxide formed during the complete combustion. The combustion reaction can be represented as below.

\[\ce{2C2H2_{(g)} + 5O2_{(g)}-> 4CO2_{(g)} + 2H2O_{(g)}}\]

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined

Calculate the percentage of water of crystallization in CuSO4. 5H2O
(H = 1, O = 16, S = 32, Cu = 64)

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.

[5.3] Percentage Composition, Empirical and Molecular Formulae
Chapter: [5.3] Percentage Composition, Empirical and Molecular Formulae
Concept: undefined >> undefined

Propane burns in air according to the following equation:

\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?

[5.1] Gay-Lussac's Law and Avogadro's Law
Chapter: [5.1] Gay-Lussac's Law and Avogadro's Law
Concept: undefined >> undefined
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