मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Why does NH3 form hydrogen bond but PH3 does not?

Advertisements
Advertisements

प्रश्न

Why does NH3 form hydrogen bond but PH3 does not?

लघु उत्तर
अति संक्षिप्त उत्तर
Advertisements

उत्तर १

Nitrogen is highly electronegative as compared to phosphorus. This causes a greater attraction of electrons towards nitrogen in NH3 than towards phosphorus in PH3. Hence, the extent of hydrogen bonding in PH3 is very less as compared to NH3.

shaalaa.com

उत्तर २

Nitrogen has an electronegativity value of 3.0, which is much higher than that of H (2.1). As a result, N-H bond is quite polar and hence NH3 undergoes intermolecular H-bonding.

Phosphorus has an electronegativity value of 2.1. Thus, the P–H bond is not polar, and hence PH3 does not undergo H-bonding.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 


Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Arrange the following in the order of the property indicated against set :
H2O, H2S, H2Se, H2Te − increasing acidic character.


 Give reactions for the following: 
O – O single bond is weaker than S – S single bond. 


Give a reason for the following:

Fluorine gives only one oxide but chlorine gives a series of oxides.


The boiling points of hydrides of group 16 are in the order:


The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.


Which of the following statement is incorrect?


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]


In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:


The correct order of ΔiHs among the following elements is


Which of the following compound is a peroxide?


______ is a radioactive element in group 16 elements.


Given below are two statements:

Statement I: The boiling point of hydrides of Group 16 elements follows the order:

H2O > H2Te > H2Se > H2S

Statement II: On the basis of molecular mass, H2O is expected to have a lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has a higher boiling point.

In the light of the above statements, choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×