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When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer. - Chemistry

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प्रश्न

When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.

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उत्तर

Anode: \[\ce{2H2O(l) -> O2(g) + 4H + (aq) + 4e^{-}}\]

Cathode: \[\ce{4H^{+} + 4e^{-} -> 2H2}\]

Overall cell reaction: \[\ce{2H2O(l) -> O2(g) + 2H2(g)}\]

pH remains the same because concentration of H+ ions remains constant.

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पाठ 3: Electrochemistry - Exercises [पृष्ठ ४०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 3 Electrochemistry
Exercises | Q III. 42. | पृष्ठ ४०

संबंधित प्रश्‍न

State Kohlrausch’s law of independent migration of ions.


State Kohlrausch Law.


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The conductivity of 0.20 mol L−1 solution of KCl is 2.48 × 10−2 S cm−1. Calculate its molar conductivity and degree of dissociation (α). Given λ0 (K+) = 73.5 S cm2 mol−1 and λ0 (C1) = 76.5 S cm2 mol−1.


The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below:

Concentration/M 0.001 0.010 0.020 0.050 0.100
102 × κ/S m−1 1.237 11.85 23.15 55.53 106.74

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10.0 grams of caustic soda when dissolved in 250 cm3 of water, the resultant gram molarity of solution is _______.

(A) 0.25 M

(B) 0.5 M

(C) 1.0 M

(D) 0.1 M


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Kohlrausch law of independent migration of ions states ____________.


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Match the items of Column I and Column II on the basis of data given below:

`E_("F"_2//"F"^-)^Θ` = 2.87 V, `"E"_(("Li"^(+))//("Li"^-))^Θ` = − 3.5V, `"E"_(("Au"^(3+))//("Au"))^Θ` = 1.4 V, `"E"_(("Br"_(2))//("Br"^-))^Θ` = 1.09 V

Column I Column II
(i) F2 (a) metal is the strongest reducing agent
(ii) Li (b) metal ion which is the weakest oxidising agent
(iii) Au3+ (c) non metal which is the best oxidising agent
(iv) Br (d) unreactive metal
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Reason: `"E"_("Ag"^+ //"Ag")` has a positive value.


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The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol−1. What is the dissociation constant of acetic acid? Choose the correct option.

\[\begin{array}{cc}
\end{array}\]\[\begin{bmatrix}
\ce{\Lambda^{\circ}_{H^+} = 350 S cm^2 mol^{-1}}\\
\ce{\Lambda^{\circ}_{CH_3COO^-} = 50 S cm^2 mol^{-1}}
\end{bmatrix}\]


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