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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.

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प्रश्न

When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.

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उत्तर

Anode: \[\ce{2H2O(l) -> O2(g) + 4H + (aq) + 4e^{-}}\]

Cathode: \[\ce{4H^{+} + 4e^{-} -> 2H2}\]

Overall cell reaction: \[\ce{2H2O(l) -> O2(g) + 2H2(g)}\]

pH remains the same because concentration of H+ ions remains constant.

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पाठ 3: Electrochemistry - Exercises [पृष्ठ ४०]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 3 Electrochemistry
Exercises | Q III. 42. | पृष्ठ ४०

संबंधित प्रश्‍न

Define “Molar conductivity”.


The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.


The conductivity of 0.001 mol L-1 solution of CH3COOH is 3.905× 10-5 S cm-1. Calculate its molar conductivity and degree of dissociation (α) Given λ°(H+)= 349.6 S cm2 mol-1 and λ°(CH3COO)= 40.9S cm2mol-1.


Define limiting molar conductivity.


The conductivity of 0.20 mol L−1 solution of KCl is 2.48 × 10−2 S cm−1. Calculate its molar conductivity and degree of dissociation (α). Given λ0 (K+) = 73.5 S cm2 mol−1 and λ0 (C1) = 76.5 S cm2 mol−1.


Write mathematical expression of molar conductivity of the given solution at infinite dilution.


 How can you determine limiting molar conductivity,   0 m for strong electrolyte and weak electrolyte?


In the plot of molar conductivity (∧m) vs square root of concentration (c1/2) following curves are obtained for two electrolytes A and B : 

Answer the following:
(i) predict the nature of electrolytes A and B.
(ii) What happens on the extrapolation of ∧m to concentration approaching for electrolytes A and B?


In the plot of molar conductivity (∧m) vs square root of concentration (c1/2), following curves are obtained for two electrolytes A and B:

Answer the following:
(i) Predict the nature of electrolytes A and B.
(ii) What happens on extrapolation of ∧m to concentration approaching zero for electrolytes A and B?


Conductivity always decreases with decrease in concentration both, for weak and strong electrolytes because of the fact that ____________.


\[\ce{Λ^0_m H2O}\] is equal to:

(i) \[\ce{Λ^0_m_{(HCl)} + \ce{Λ^0_m_{(NaOH)} - \ce{Λ^0_m_{(NaCl)}}}}\]

(ii) \[\ce{Λ^0_m_{(HNO_3)} + \ce{Λ^0_m_{(NaNO_3)} - \ce{Λ^0_m_{(NaOH)}}}}\]

(iii) \[\ce{Λ^0_{(HNO_3)} + \ce{Λ^0_m_{(NaOH)} - \ce{Λ^0_m_{(NaNO_3)}}}}\]

(iv) \[\ce{Λ^0_m_{(NH_4OH)} + \ce{Λ^0_m_{(HCl)} - \ce{Λ^0_m_{(NH_4Cl)}}}}\]


Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?


Match the items of Column I and Column II on the basis of data given below:

`E_("F"_2//"F"^-)^Θ` = 2.87 V, `"E"_(("Li"^(+))//("Li"^-))^Θ` = − 3.5V, `"E"_(("Au"^(3+))//("Au"))^Θ` = 1.4 V, `"E"_(("Br"_(2))//("Br"^-))^Θ` = 1.09 V

Column I Column II
(i) F2 (a) metal is the strongest reducing agent
(ii) Li (b) metal ion which is the weakest oxidising agent
(iii) Au3+ (c) non metal which is the best oxidising agent
(iv) Br (d) unreactive metal
(v) Au (e) anion that can be oxidised by Au3+
(vi) Li+ (f) anion which is the weakest reducing agent
(vii) F (g) metal ion which is an oxidising agent

The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol–1 respectively. The limiting molar conductivity Λ° for NaBr is ______.


Which of the following halogen acids is the strongest reducing agent?


The variation of molar conductivity with concentration of an electrolyte (X) m aqueous solution is shown in the given figure.

The electrolyte X is ______.


Which of the following solutions will have the highest conductivity at 298 K? 


The solution of two electrolytes A and B are diluted. ^m of B increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Give a reason.


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