Question

The limiting molar conductivities Λ^° for NaCl, KBr and KCl are 126, 152 and 150 S cm² mol^–1 respectively. The limiting molar conductivity Λ^° for NaBr is ______.

पर्याय

• 278 S cm² mol^–1 

• 176 S cm² mol^–1 

• 128 S cm² mol^–1 

• 302 S cm² mol^–1 

Answer 1

The limiting molar conductivities Λ^° for NaCl, KBr and KCl are 126, 152 and 150 S cm² mol^–1 respectively. The limiting molar conductivity Λ^° for NaBr is 128 S cm² mol^–1.

Explanation:

The limiting molar conductivities of NaCl, KBr and KCl are 126, 152 and 150 S cm² mol^–1 respectively.

The limiting molar conductivity Λ^° for NaBr is calculated by the following expression.

`Lambda_(NaBr)^infty = Lambda_(NaCl)^infty + Lambda_(KBr)^infty - Lambda_(KCl)^infty`

= 126 + 152 – 150

= 128 S cm² mol^–1