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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Define “Molar conductivity”.

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प्रश्न

Define “Molar conductivity”.

Define molar conductivity for the solution of an electrolyte.

Define molar conductivity of an electrolytic solution.

व्याख्या
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उत्तर

Molar conductivity is the conductance of a volume of solution containing 1 mole of dissolved electrolyte when placed between two parallel electrodes 1 cm apart and large enough to contain between them all the solution.

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पाठ 2: Electrochemistry - Exercises [पृष्ठ ५९]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 2 Electrochemistry
Exercises | Q 2.7 (ii) | पृष्ठ ५९
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
REVIEW EXERCISES | Q 3.41 ii. | पृष्ठ १६५
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
REVIEW EXERCISES | Q 3.40 i. | पृष्ठ १६५
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
REVIEW EXERCISES | Q 3.38 (ii) | पृष्ठ १६५
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
VERY SHORT ANSWER TYPE QUESTIONS | Q 18. i. | पृष्ठ १९२
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
SHORT ANSWER TYPE QUESTIONS | Q 6. i. | पृष्ठ १९४
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
LONG ANSWER TYPE QUESTIONS | Q 2. iii. | पृष्ठ १९६
नूतन Chemistry [English] Class 12 ISC
पाठ 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.7 ii. | पृष्ठ २११

संबंधित प्रश्‍न

Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given: Conductivity of 0.1 M KCl solution is 1.29 S m-1 .]


State Kohlrausch’s law of independent migration of ions.


The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.


The conductivity of 0.001 mol L-1 solution of CH3COOH is 3.905× 10-5 S cm-1. Calculate its molar conductivity and degree of dissociation (α) Given λ°(H+)= 349.6 S cm2 mol-1 and λ°(CH3COO)= 40.9S cm2mol-1.


The conductivity of 0.20 mol L−1 solution of KCl is 2.48 × 10−2 S cm−1. Calculate its molar conductivity and degree of dissociation (α). Given λ0 (K+) = 73.5 S cm2 mol−1 and λ0 (C1) = 76.5 S cm2 mol−1.


Why does the conductivity of a solution decrease with dilution?


Define the following terms: Molar conductivity (m)


The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol1. Calculate its degree of dissociation and dissociation constant. Given \[\ce{λ^0_{(H^+)}}\] = 349.6 S cm2 mol1 and \[\ce{λ^0_{(HCOO^-)}}\] = 54.6 S cm2 mol1.


The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below:

Concentration/M 0.001 0.010 0.020 0.050 0.100
102 × κ/S m−1 1.237 11.85 23.15 55.53 106.74

Calculate ∧m for all concentrations and draw a plot between ∧m and c1/2. Find the value of `Lambda_m^0`.


Conductivity of 0.00241 M acetic acid is 7.896 × 10−5 S cm−1. Calculate its molar conductivity and if `Lambda_m^0` for acetic acid is 390.5 S cm2 mol−1, what is its dissociation constant?


The conductivity of 0.02 M AgNO3 at 25°C is 2.428 × 103 Ω1 cm1. What is its molar conductivity?


Write mathematical expression of molar conductivity of the given solution at infinite dilution.


A steady current of 2 amperes was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO4and ZnSO4 until 2.8g of Fe deposited at the cathode of cell X. How long did the current flow? Calculate the mass of Zn deposited at the cathode of cell Y. 
(Molar mass: Fe=56g mol-1,Zn=65.3g mol-1,1F=96500C mol-1)


Conductivity always decreases with decrease in concentration both, for weak and strong electrolytes because of the fact that ____________.


Kohlrausch law of independent migration of ions states ____________.


Which of the statements about solutions of electrolytes is not correct?


\[\ce{Λ^0_m H2O}\] is equal to:

(i) \[\ce{Λ^0_m_{(HCl)} + \ce{Λ^0_m_{(NaOH)} - \ce{Λ^0_m_{(NaCl)}}}}\]

(ii) \[\ce{Λ^0_m_{(HNO_3)} + \ce{Λ^0_m_{(NaNO_3)} - \ce{Λ^0_m_{(NaOH)}}}}\]

(iii) \[\ce{Λ^0_{(HNO_3)} + \ce{Λ^0_m_{(NaOH)} - \ce{Λ^0_m_{(NaNO_3)}}}}\]

(iv) \[\ce{Λ^0_m_{(NH_4OH)} + \ce{Λ^0_m_{(HCl)} - \ce{Λ^0_m_{(NH_4Cl)}}}}\]


Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.


When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.


Write the cell reaction of a lead storage battery when it is discharged. How does the density of the electrolyte change when the battery is discharged?


Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?


Match the items of Column I and Column II on the basis of data given below:

`E_("F"_2//"F"^-)^Θ` = 2.87 V, `"E"_(("Li"^(+))//("Li"^-))^Θ` = − 3.5V, `"E"_(("Au"^(3+))//("Au"))^Θ` = 1.4 V, `"E"_(("Br"_(2))//("Br"^-))^Θ` = 1.09 V

Column I Column II
(i) F2 (a) metal is the strongest reducing agent
(ii) Li (b) metal ion which is the weakest oxidising agent
(iii) Au3+ (c) non metal which is the best oxidising agent
(iv) Br (d) unreactive metal
(v) Au (e) anion that can be oxidised by Au3+
(vi) Li+ (f) anion which is the weakest reducing agent
(vii) F (g) metal ion which is an oxidising agent

Assertion: Copper sulphate can be stored in zinc vessel.

Reason: Zinc is less reactive than copper.


Consider figure and answer the question to given below.

How will the concentration of Zn2+ ions and Ag+ ions be affected after the cell becomes ‘dead’?


The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol–1 respectively. The limiting molar conductivity Λ° for NaBr is ______.


Which of the following increases with the increase in the concentration of the solution?


The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol−1. What is the dissociation constant of acetic acid? Choose the correct option.

\[\begin{array}{cc}
\end{array}\]\[\begin{bmatrix}
\ce{\Lambda^{\circ}_{H^+} = 350 S cm^2 mol^{-1}}\\
\ce{\Lambda^{\circ}_{CH_3COO^-} = 50 S cm^2 mol^{-1}}
\end{bmatrix}\]


Molar conductivity of substance “A” is 5.9 × 103 S/m and “B” is 1 × 10–16 S/m. Which of the two is most likely to be copper metal and why?


Given below are two statements:

Statements I: The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte).

Statement II: Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements, choose the most appropriate answer from the options given below:


The solubility of Co2[Fe(CN)6] in water at 25°C from the following data:

Conductivity of saturated solution of Co2[Fe(CN)6] = 2.06 × 10−6 ohm−1 cm−1 and that of water = 4.1 × 10−7 ohm−1 cm−1. The ionic molar conductivities of Co2+ and [Fe(CN)6]4− are 86 and 444 ohm−1 cm2 mol−1 respectively, is ______ × 10−6 mol/L.


Which of the following solutions of KCl will have the highest value of molar conductivity?


The unit of molar conductivity is ______.


Which of the following solutions will have the highest conductivity at 298 K? 


The specific conductance of 2.5 × 10-4 M formic acid is 5.25 × 10-5 ohm-1 cm-1. Calculate its molar conductivity and degree of dissociation.

Given `λ°_("H"^+)` = 349.5 ohm-1 cm2 mol-1 and

`λ°_("HCOO"^-)  = 50.5 " ohm"^-1 "cm"^2  "mol"^-1`


The resistance of a conductivity cell with a 0.1 M KCl solution is 200 ohm. When the same cell is filled with a 0.02 M NaCl solution, the resistance is 1100 ohm. If the conductivity of 0.1 M KCl solution is 0.0129 ohm-1 cm-1, calculate the cell constant and molar conductivity of 0.02 M NaCl solution.


The solution of two electrolytes A and B are diluted. ^m of B increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Give a reason.


Suggest a way to determine the \[\ce{\Lambda^{\circ}_m}\] value of water.


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