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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Define “Molar conductivity. - Chemistry

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प्रश्न

Define “Molar conductivity”.

Define molar conductivity for the solution of an electrolyte.

Define molar conductivity of an electrolytic solution.

व्याख्या
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उत्तर १

Molar conductivity is the conductance of a volume of solution containing 1 mole of dissolved electrolyte when placed between two parallel electrodes 1 cm apart and large enough to contain between them all the solution.

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उत्तर २

The conductivity, which is shown by all the ions when 1 mol of electrolyte is dissolved in the solution, is called molar conductivity; it is expressed by ∧m (lambda). If 1 mol of electrolyte is present in Vm cm3 of electrolyte solution, then ∧m = κ × V

= `(kappa xx 1000)/"Molarity" = (kappa xx 1000)/M`

Its unit is ohm−1 cm2 mol1 or S cm2 mol1.

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Notes

Students should refer to the answer according to their questions

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Electrochemistry - Exercises [पृष्ठ ५९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 2 Electrochemistry
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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
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'NCERT TEXT-BOOK' Exercises | Q 3.7 ii. | पृष्ठ २११
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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
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संबंधित प्रश्‍न

Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given: Conductivity of 0.1 M KCl solution is 1.29 S m-1 .]


State Kohlrausch’s law of independent migration of ions.


The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.


Define limiting molar conductivity.


The conductivity of 0.20 mol L−1 solution of KCl is 2.48 × 10−2 S cm−1. Calculate its molar conductivity and degree of dissociation (α). Given λ0 (K+) = 73.5 S cm2 mol−1 and λ0 (C1) = 76.5 S cm2 mol−1.


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\[\begin{array}{cc}
\end{array}\]\[\begin{bmatrix}
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