Advertisements
Advertisements
प्रश्न
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.

Advertisements
उत्तर
Area of octagon = Area of (ABDC) + Area of (CDFE) + Area of (EFHG)

= `{1/2 [(5+11) xx 4] + (11 xx 5) + 1/2 [(5 + 11) xx 4]}m^2`
= `{1/2 (16 xx 4) + 55 + 1/2 (16 xx4)}m^2`
= `{1/2 xx 64 + 5 + 1/2 xx 64}m^2`
= {32 + 55 + 32}m2
= 119m2
APPEARS IN
संबंधित प्रश्न
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
The area of a trapezium become 4 times if its height gets doubled.
