Advertisements
Advertisements
प्रश्न
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.
Advertisements
उत्तर
Area of octagon = Area of (ABDC) + Area of (CDFE) + Area of (EFHG)
= `{1/2 [(5+11) xx 4] + (11 xx 5) + 1/2 [(5 + 11) xx 4]}m^2`
= `{1/2 (16 xx 4) + 55 + 1/2 (16 xx4)}m^2`
= `{1/2 xx 64 + 5 + 1/2 xx 64}m^2`
= {32 + 55 + 32}m2
= 119m2
APPEARS IN
संबंधित प्रश्न
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
The area of the trapezium, if the parallel sides are measuring 8 cm and 10 cm and the height 5 cm is
When the non-parallel sides of a trapezium are equal then it is known as
The table top is in the shape of a trapezium with measurements given in the figure. Find the cost of the glass used to cover the table at the rate of ₹ 6 per 10 sq.cm
