Advertisements
Advertisements
प्रश्न
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
Advertisements
उत्तर
Given:
Area of the trapezium = 28 cm2
Length of one of its parallel sides = 6 cm
Altitude = 4 cm
Let the other side be x cm.
Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Altitude })\]
\[ \Rightarrow 28=\frac{1}{2}\times(6+x)\times(4)\]
\[ \Rightarrow 28 = 2 \times (6 + x)\]
\[ \Rightarrow 6+x=\frac{28}{2}=14\]
\[ \Rightarrow x=14-6=8 cm\]
Hence, the length of the other parallel side of the trapezium is 8 cm.
APPEARS IN
संबंधित प्रश्न
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m2 and whose height is 280 cm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
The area of a trapezium become 4 times if its height gets doubled.
Find the area of the following fields. All dimensions are in metres.

