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The ratio of maximum and minimum intensities in an interference pattern is 36 : 1. What is the ratio of the amplitudes of the two interfering waves?

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प्रश्न

The ratio of maximum and minimum intensities in an interference pattern is 36 : 1. What is the ratio of the amplitudes of the two interfering waves?

संख्यात्मक
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उत्तर

`"I"_"max"/"I"_"min" = 36/1`

`"I"_"max"/"I"_"min" = ("a"_1 + "a"_2)^2/("a"_1 - "a"_2)^2`

`("a"_1 + "a"_2)^2/("a"_1 - "a"_2)^2 = 36/1 = 6^2/1^2`

`("a"_1 + "a"_2)/("a"_1 - "a"_2) = 6/1`

a1 + a2 = 6a1 - 6a2

a2 + 6a2 = 6a1 - a1 

7a2 = 5a1 

`7/5 = "a"_1/"a"_2`

a1 : a2 = 7 : 5

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पाठ 7: Wave Optics - Evaluation [पृष्ठ १०४]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 7 Wave Optics
Evaluation | Q 1. | पृष्ठ १०४

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