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प्रश्न
The following table gives the activities of a project and their duration in days
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 |
| Duration | 5 | 8 | 6 | 7 | 5 | 4 | 8 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
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उत्तर
E1 = 0
E2 = 0 + 5 = 5
E3 = (0 + 8) or (5 + 6)
Whichever is maximum
= 11
E4 = (11 + 5) or (5 + 7)
Whichever is maximum
= 16
E5 = (11 + 4) or (16 + 8)
Whichever is maximum
= 24
L5 = 24
L4 = 24 – 8 = 16
L3 = (24 – 4) or (16 – 5)
whichever is minimum
= 11
L2 = (16 – 6) or (16 – 7)
whichever is minimum
= 5
L1 = (5 – 5) or (11 – 8)
whichever is minimum
L1 = 0
| Activity | Duration tij |
EST | EFT = EST + tij | LST = LFT – tij | LFT |
| 1 - 2 | 5 | 0 | 5 | 5 – 5 = 0 | 5 |
| 1 - 3 | 8 | 0 | 8 | 11 – 8 = 3 | 11 |
| 2 - 3 | 6 | 5 | 11 | 11 – 6 = 5 | 11 |
| 2 - 4 | 7 | 5 | 12 | 16 – 7 = 9 | 16 |
| 3 - 4 | 5 | 11 | 16 | 16 – 5 = 11 | 16 |
| 3 - 5 | 4 | 11 | 15 | 24 – 4 = 20 | 24 |
| 4 - 5 | 8 | 16 | 24 | 24 – 8 = 16 | 24 |
Since EFT and LFT are same in 1 - 2, 2 - 3, 3 - 4 and 4 - 5.
Hence the critical path is 1 - 2 - 3 - 4 - 5 and the duration time taken is 24 days.
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संबंधित प्रश्न
Draw the event oriented network for the following data:
| Events | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Immediate Predecessors | - | 1 | 1 | 2, 3 | 3 | 4, 5 | 5, 6 |
Construct the network for each the projects consisting of various activities and their precedence relationships are as given below:
| Activity | A | B | C | D | E | F | G | H | I | J | K |
| Immediate Predecessors | - | - | - | A | B | B | C | D | E | H, I | F, G |
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
| Jobs | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 | 4 - 6 | 5 - 6 |
| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
A Project has the following time schedule
| Activity | 1 - 2 | 1 - 6 | 2 - 3 | 2 - 4 | 3 - 5 | 4 - 5 | 6 - 7 | 5 - 8 | 7 - 8 |
| Duration (in days) | 7 | 6 | 14 | 5 | 11 | 7 | 11 | 4 | 18 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
The following table use the activities in a construction projects and relevant information
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 4 - 5 |
| Duration (in days) |
22 | 27 | 12 | 14 | 6 | 12 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
In constructing the network which one of the following statements is false?
Which of the following is not correct?
Network problems have the advantage in terms of project
In critical path analysis, the word CPM mean
Draw a network diagram for the following activities.
| Activity code | A | B | C | D | E | F | G | H | I | J | K |
| Predecessor activity | - | A | A | A | B | C | C | C, D | E, F | G, H | I, J |
