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प्रश्न
Construct the network for the project whose activities are given below.
| Activity | 0 - 1 | 1 - 2 | 1 - 3 | 2 - 4 | 2 - 5 | 3 - 4 | 3 - 6 | 4 - 7 | 5 - 7 | 6 - 7 |
| Duration (in week) | 3 | 8 | 12 | 6 | 3 | 3 | 8 | 5 | 3 | 8 |
Calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity. Determine the critical path and the project completion time.
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उत्तर

E1 = 0 + 3 = 3
E2 = E1 + t12 = 8 + 3 = 11
E3 = 3 + 12 = 15
E4 = 15 + 3 = 18
E5 = E2 + 3 = 11 + 3 = 14
E6 = E3 + 8 = 15 + 8 = 23
E7 = E6 + 8 = 23 + 8 = 31
L7 = 31
L6 = L7 – 8 = 31 – 8 = 23
L5 = L7 – 3 = 31 – 3 = 28
L4 = L7 – 5 = 31 – 5 = 26
L3 = L6 – 8 = 23 – 8 = 15
L2 = L5 – 3 or L4 which is minimum
= (28 – 3) or (26 – 6)
= 25 or 20
= 20 (which is minimum)
L1 = L2 – 8 or L3 – 12
whichever is minimum
= (20 – 8) or (15 – 12)
= 12 or 3
= 3
L0 = 0
| Activity | Duration tij |
EST | EFT = EST + tij | LST = LFT – tij | LFT |
| 0 - 1 | 3 | 0 | 3 | 3 | 3 |
| 1 - 2 | 8 | 3 | 11 | 20 – 8 = 12 | 20 |
| 1 - 3 | 12 | 3 | 15 | 15 – 12 = 3 | 15 |
| 2 - 4 | 6 | 11 | 17 | 26 – 6= 20 | 26 |
| 2 - 5 | 3 | 11 | 14 | 28 – 3 = 25 | 28 |
| 3 - 4 | 3 | 15 | 18 | 26 – 3 = 23 | 26 |
| 3 - 6 | 8 | 15 | 23 | 23 – 8 = 15 | 23 |
| 4 - 7 | 5 | 18 | 23 | 31 – 5 = 26 | 31 |
| 5 - 7 | 3 | 14 | 14 | 31 – 3 = 28 | 31 |
| 6 - 7 | 8 | 23 | 31 | 31 – 8 = 23 | 31 |
The critical path is 0 - 1 - 3 - 6 - 7 and the project completion time is 31 weeks.
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संबंधित प्रश्न
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
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| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
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| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 |
| Duration | 5 | 8 | 6 | 7 | 5 | 4 | 8 |
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| Duration (in days) |
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