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प्रश्न
A Project has the following time schedule
| Activity | 1 - 2 | 1 - 6 | 2 - 3 | 2 - 4 | 3 - 5 | 4 - 5 | 6 - 7 | 5 - 8 | 7 - 8 |
| Duration (in days) | 7 | 6 | 14 | 5 | 11 | 7 | 11 | 4 | 18 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
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उत्तर
E1 = 0
E2 = 0 + 7 = 7
E3 = 7 + 14 = 21
E4 = 7 + 5 = 12
E5 = 21 + 11 or (12 + 7)
Whichever is maximum
= 32
E6 = 0 + 6 = 6
E7 = 6 + 11 = 17
E8 = 17 + 18 = 35
L8 = 35
L7 = 35 – 18 = 17
L6 = 17 – 11 = 6
L5 = 35 – 4 = 31
L4 = 32 – 7 = 25
L3 = 32 – 11 = 21
L2 = (21 – 14) or (25 – 5)
whichever is minimum
= 7
L1 = 7 – 7 = 0
| Activity | Duration tij |
EST | EFT = EST + tij | LST = LFT – tij | LFT |
| 1 - 2 | 7 | 0 | 7 | 7 – 7 = 0 | 7 |
| 1 - 6 | 6 | 0 | 6 | 7 – 6 = 1 | 7 |
| 2 - 3 | 14 | 7 | 21 | 21 – 14 = 7 | 21 |
| 2 - 4 | 5 | 7 | 12 | 25 – 5 = 20 | 25 |
| 3 - 5 | 11 | 21 | 32 | 31 – 11 = 21 | 32 |
| 4 - 5 | 7 | 12 | 19 | 32 – 25 = 7 | 14 |
| 6 - 7 | 11 | 6 | 17 | 18 – 11 = 7 | 18 |
| 5 - 8 | 4 | 32 | 36 | 36 – 4 = 32 | 36 |
| 7 - 8 | 18 | 17 | 36 | 36 – 18 = 18 | 36 |
Since EFT and LFT are same in 1 - 2, 2 - 3, 3 - 5 and 5 - 8.
Hence the critical path is 1 - 2 - 3 - 5 - 8 and the duration of time taken is 36 days.
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संबंधित प्रश्न
Draw the event oriented network for the following data:
| Events | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Immediate Predecessors | - | 1 | 1 | 2, 3 | 3 | 4, 5 | 5, 6 |
Construct the network for the project whose activities are given below.
| Activity | 0 - 1 | 1 - 2 | 1 - 3 | 2 - 4 | 2 - 5 | 3 - 4 | 3 - 6 | 4 - 7 | 5 - 7 | 6 - 7 |
| Duration (in week) | 3 | 8 | 12 | 6 | 3 | 3 | 8 | 5 | 3 | 8 |
Calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity. Determine the critical path and the project completion time.
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
| Jobs | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 | 4 - 6 | 5 - 6 |
| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
One of the conditions for the activity (i, j) to lie on the critical path is
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Draw a network diagram for the following activities.
| Activity code | A | B | C | D | E | F | G | H | I | J | K |
| Predecessor activity | - | A | A | A | B | C | C | C, D | E, F | G, H | I, J |
A Project has the following time schedule
| Activity | 1 - 2 | 2 - 3 | 2 - 4 | 3 - 5 | 4 - 6 | 5 - 6 |
| Duration (in days) |
6 | 8 | 4 | 9 | 2 | 7 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
The following table gives the characteristics of the project
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 3 - 4 | 3 - 5 | 4 - 6 | 5 - 6 | 6 - 7 |
| Duration (in days) |
5 | 10 | 3 | 4 | 6 | 6 | 5 | 5 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
