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Solve: ydx – xdy = x2ydx. - Mathematics

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प्रश्न

Solve: ydx – xdy = x2ydx.

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उत्तर

Given equation is ydx – xdy = x2ydx.

⇒ ydx – x2y dx = xdy

⇒ y(1 – x2)dx = xdy

⇒ `((1 - x^2)/x)"d"x = "dy"/y`

⇒ `(1/x - x)"d"x = "dy"/y`

Integrating both sides we get

`int(1/x - x)"d"x = int "dy"/y`

⇒ `log x - x^2/2` = log y + log c

⇒ `log x - x^2/2` = log yc

⇒ log y – log c = `x^2/2`

⇒ `log x/(y"c") = x^2/2`

⇒ `x/(y"c") = "e"^(x^2/2)`

⇒ `(y"c")/x = "e"^((-x^2)/2`

⇒ yc = `x"e"^((-x^2)/2`

∴ y = `1/"c" * x"e"^((-x^2)/2`

⇒ y = `"k"x"e"^((-x^2)/2`  ......`[because "k" = 1/"c"]`

Hence, the required solution is y = `"k"x"e"^((-x^2)/2`.

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पाठ 9: Differential Equations - Exercise [पृष्ठ १९३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 9 Differential Equations
Exercise | Q 8 | पृष्ठ १९३

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