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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Solve the following problem. Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg.

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प्रश्न

Solve the following problem.

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg.

बेरीज
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उत्तर

Given: M = 6.4 × 1023 kg, R = 3.4 × 103 km = 3.4 × 106 m, 

To find: Acceleration due to gravity on the surface of the Mars (gM)

Formula: g = `"GM"/"R"^2`

Calculation: As, G = 6.67 × 10-11 Nm2/kg2

From formula,

`"g"_"M" = (6.67 xx 10^-11 xx 6.4 xx 10^23)/(3.4 xx 10^6)^2 = (6.67 xx 6.4)/(3.4 xx 3.4)`

= antilog{log(6.67) + log(6.4) - log(3.4) - log(3.4)}

= antilog{(0.8241) + (0.8062) - (0.5315) - (0.5315)}

= antilog {0.5673}

= 3.693 m/s2

Acceleration due to gravity on the surface of Mars is 3.693 m/s2.

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पाठ 5: Gravitation - Exercises [पृष्ठ ९९]

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बालभारती Physics [English] Standard 11 Maharashtra State Board
पाठ 5 Gravitation
Exercises | Q 4. (viii) | पृष्ठ ९९

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