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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Solve the following problem. What is the gravitational potential due to the Earth at a point which is at a height of 2RE above the surface of the Earth?

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प्रश्न

Solve the following problem.

What is the gravitational potential due to the Earth at a point which is at a height of 2RE above the surface of the Earth?
(Mass of the Earth is 6 × 1024 kg, radius of the Earth = 6400 km and G = 6.67 × 10–11 N m2 kg–2)

बेरीज
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उत्तर

Given: M = 6 × 1024 kg, RE = 6400 km = 6.4 × 106 m, G = 6.67 × 10–11 N m2/kg2, h = 2RE 

To find: Gravitational potential (V)

Formula: V = -`"GM"/"r"`

Calculation: From formula,

V = `- "GM"/("R"_"E" + 2"R"_"E")`

`= - (6.67 xx 10^-11 xx 6 xx 10^24)/(3 xx 6.4 xx 10^6)`

`= -(6.67 xx 2)/6.4 xx 10^7`

= - 2.08 × 107 J kg-1

Negative sign indicates the attractive nature of gravitational potential.

Gravitational potential due to Earth will be 2.08 × 107 J kg-1 towards the centre of the Earth.

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पाठ 5: Gravitation - Exercises [पृष्ठ ९९]

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बालभारती Physics [English] Standard 11 Maharashtra State Board
पाठ 5 Gravitation
Exercises | Q 4. (xii) | पृष्ठ ९९

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