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Solve the following : Find the amount of an ordinary annuity if a payment of ₹500 is made at the end of every quarter for 5 years at the rate of 12% per annum compounded quarterly. [(1.03)20 = 1.8061] - Mathematics and Statistics

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प्रश्न

Solve the following :

Find the amount of an ordinary annuity if a payment of ₹500 is made at the end of every quarter for 5 years at the rate of 12% per annum compounded quarterly. [(1.03)20 = 1.8061]

बेरीज
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उत्तर

Given, C = ₹500
Amount is invested at the end of every quarter.
∴ It is an immediate annuity.
Rate of interest is 12% p.a.

∴ r = `(12)/(4)`% = 3% per quarter

∴ i = `"r"/(100) = (3)/(100)`  0..03
The period is of 5 years and payment is made on quarterly basis.
∴ n = 5 x 4 = 20

Since, A = `"C"/"i"[(1 + "i")^"n" - 1]`

= `(500)/(0.03)[(1 + 0.03)^20 - 1]`

= `(500)/(0.03)[(1.03)^20 - 1]`

= `(500)/(0.03)(1.8061 - 1)`

= `(500)/(0.03) xx (0.8061)`

= `(403.05)/(0.03)`

= `(40305)/(3)`
= ₹13,435
∴ Amount of ordinary annuity is ₹13,435.

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पाठ 2: Insurance and Annuity - Miscellaneous Exercise 2 [पृष्ठ ३१]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 2 Insurance and Annuity
Miscellaneous Exercise 2 | Q 4.14 | पृष्ठ ३१

संबंधित प्रश्‍न

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In annuity calculations, the interest is usually taken as ______


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[Given (1.1)4 = 1.4641]


The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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