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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A 35-year old person takes a policy for ₹ 1,00,000 for a period of 20 years. The rate of premium is ₹ 76 and the average rate of bonus is ₹ 7 per thousand p.a. If he dies after paying 10 annual premi - Mathematics and Statistics

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प्रश्न

A 35-year old person takes a policy for ₹ 1,00,000 for a period of 20 years. The rate of premium is ₹ 76 and the average rate of bonus is ₹ 7 per thousand p.a. If he dies after paying 10 annual premiums, what amount will his nominee receive?

बेरीज
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उत्तर

Given, Policy value = ₹ 1 lakh,

Period of the policy = 20 years

But, the person dies after paying 10 annual premiums.

∴ Nominee will get entire Policy value of ₹ 1,00,000 on account of death.

Also, rate of bonus is ₹ 7 per thousand per annum

∴ Bonus (per year) = `(7)/(1,000) xx 1,00,000`

= ₹ 700

∴ Bonus for 10 years = 700 x 10 = ₹ 7,000

∴ Amount received by his nominee

= Policy value + Bonus

= 1,00,000 + 7,000

= ₹ 1,07,000

∴ Amount received by his nominee is ₹ 1,07,000.

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पाठ 2.2: Insurance and Annuity - Q.4

संबंधित प्रश्‍न

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An annuity immediate is to be paid for some years at 12% p.a. The present value of the annuity is ₹ 10,000 and the accumulated value is ₹ 20,000. Find the amount of each annuity payment


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Choose the correct alternative :

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If payments of an annuity fall due at the beginning of every period, the series is called annuity __________.


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Annuity contingent begins and ends on certain fixed dates.


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A shopkeeper insures his shop and godown valued at ₹5,00,000 and ₹10,00,000 respectively for 80 % of their values. If the rate of premium is 8 %, find the total annual premium.


Solve the following :

Find the amount a company should set aside at the end of every year if it wants to buy a machine expected to cost ₹1,00,000 at the end of 4 years and interest rate is 5% p. a. compounded annually. [(1.05)4 = 1.21550625]


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= 2,00,000 [1 – 0.7513]

= ₹ `square`


The future amount, A = ₹ 10,00,000

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A = `"C"/"I" [(1 + "i")^"n" - 1]`

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= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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