Advertisements
Advertisements
प्रश्न
Solve the following equation for x:
`7^(2x+3)=1`
Advertisements
उत्तर
`7^(2x+3)=1`
`rArr7^(2x+3)=7^0`
⇒ 2x + 3 = 0
⇒ 2x = -3
`rArrx=-3/2`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Which of the following is (are) not equal to \[\left\{ \left( \frac{5}{6} \right)^{1/5} \right\}^{- 1/6}\] ?
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
(256)0.16 × (256)0.09
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
