Advertisements
Advertisements
प्रश्न
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Advertisements
उत्तर
We have to prove that `(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Let x = `(2^n+2^(n-1))/(2^(n+1)-2^n)`
`=(2^n(1+1xx2^-1))/(2^n(2^1-1))`
`=(1+1/2)/(2-1)`
`rArrx=3/2`
Hence, `(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(2x^-2y^3)^3`
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Simplify the following:
`(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))`
Simplify:
`(0.001)^(1/3)`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
Determine `(8x)^x,`If `9^(x+2)=240+9^x`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
When simplified \[(256) {}^{- ( 4^{- 3/2} )}\] is
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
