मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Simplify : 2 Sin30 + 3 Tan45.

Advertisements
Advertisements

प्रश्न

Simplify : 2 sin30 + 3 tan45.

Advertisements

उत्तर

2.sin30 + 3.tan45
= 2 × `1/2` + 3 × 1
= 1 + 3
= 4
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2018-2019 (March) Balbharati Model Question Paper Set 3

संबंधित प्रश्‍न

If sinθ + sin2 θ = 1, prove that cos2 θ + cos4 θ = 1


Prove the following trigonometric identities.

tan2 θ − sin2 θ = tan2 θ sin2 θ


Prove the following trigonometric identities.

(sec A − cosec A) (1 + tan A + cot A) = tan A sec A − cot A cosec A


Prove the following trigonometric identities.

`cot^2 A cosec^2B - cot^2 B cosec^2 A = cot^2 A - cot^2 B`


Prove the following identities:

(1 – tan A)2 + (1 + tan A)2 = 2 sec2A


Prove that:

`(cosecA - sinA)(secA - cosA) = 1/(tanA + cotA)`


Prove that:

(cosec A – sin A) (sec A – cos A) sec2 A = tan A


`sin theta (1+ tan theta) + cos theta (1+ cot theta) = ( sectheta+ cosec  theta)`


Prove the following identities:

`(sec theta + tan theta)/(sec theta - tan theta) = (sec theta + tan theta)^2 = 1 + 2 tan^2 theta + 2 sec theta tan theta`


`(sin theta +cos theta )/(sin theta - cos theta)+(sin theta- cos theta)/(sin theta + cos theta) = 2/((sin^2 theta - cos ^2 theta)) = 2/((2 sin^2 theta -1))`


Prove that `(sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/(secθ - tanθ)`


If 5x = sec θ and \[\frac{5}{x} = \tan \theta\]find the value of \[5\left( x^2 - \frac{1}{x^2} \right)\] 


Prove the following identity : 

`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`


Prove the following identity : 

`sec^4A - sec^2A = sin^2A/cos^4A`


Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A.


Prove that:

`(sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = 2/(2 sin^2 A - 1)`


If A + B = 90°, show that `(sin B + cos A)/sin A = 2tan B + tan A.`


sec 60° = ?


If tan θ – sin2θ = cos2θ, then show that `sin^2θ = 1/2`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×