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प्रश्न
Prove that:
`(sinA - cosA)(1 + tanA + cotA) = secA/(cosec^2A) - (cosecA)/(sec^2A)`
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उत्तर
`(sinA - cosA)(1 + tanA + cotA)`
= `sinA + (sin^2A)/cosA + cosA - cosA - sinA - (cos^2A)/sinA`
= `(sin^2A)/cosA - (cos^2A)/sinA`
= `secA/(cosec^2A) - (cosecA)/(sec^2A)`
संबंधित प्रश्न
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Activity:
sec2θ = 1 + `square` ...[Fundamental trigonometric identity]
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