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On radiating (sending out) an AM modulated signal, the total radiated power is due to energy carried by ωc, ωc – ωm and ωc + ωm. - Physics

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प्रश्न

On radiating (sending out) an AM modulated signal, the total radiated power is due to energy carried by ωc, ωc – ωm and ωc + ωm. Suggest ways to minimise cost of radiation without compromising on information.

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उत्तर

Sideband frequencies: The AM wave contains three frequencies ωc, (ωc + ωm) and (ωc – ωm), ωc is called carrier frequency, (ωc + ωm) and ( ωc – ωm) are called sideband frequencies.

c + ωm) = Upper sideband (USB) frequency

c – ωm) =Lower sideband (LSB) frequency

Sideband frequencies are generally close to the carrier frequency.

Only side band frequencies contain information in amplitude modulated signal, [only (ωc+ ωm) and (ωc + ωm)].

Here, the total radiated power is due to energy carried by ωc, (ωc – ωm) and (ωcm)

For reduction of the cost of radiation without compromising on information, ωc can be left and transmit the frequencies (ωc + ωm), (ωc – ωm) or both (ωc + ωm) and (ωc – ωm).

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पाठ 15: Communication Systems - Exercise [पृष्ठ १०३]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 12
पाठ 15 Communication Systems
Exercise | Q 15.25 | पृष्ठ १०३

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