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Obtain the differential equation by eliminating the arbitrary constants from the following equation: y = Ae5x + Be-5x

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प्रश्न

Obtain the differential equation by eliminating the arbitrary constants from the following equation:

y = Ae5x + Be-5x 

बेरीज
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उत्तर

y = Ae5x + Be-5x      ...(1)

Differentiating twice w.r.t. x, we get

`"dy"/"dx" = "Ae"^"5x" xx 5 + "Be"^(- "5x") xx (- 5)`

∴ `"dy"/"dx" = 5"Ae"^"5x" - 5"Be"^(- "5x")`

and `("d"^2"y")/"dx"^2 = "Ae"^"5x" xx 5 + "Be"^(- "5x") xx (- 5)`

`= 25"Ae"^"5x" + 25"Be"^(- "5x")`

`= 25("Ae"^"5x" + "Be"^(- "5x")) = 25"y"`   ....[By(1)]

∴ `("d"^2"y")/"dx"^2 - 25"y" = 0`

This is the required D.E.

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पाठ 6: Differential Equations - Exercise 6.2 [पृष्ठ १९६]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.2 | Q 1.05 | पृष्ठ १९६

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