मराठी

Let R be the set of real numbers and f: R → R be the function defined by f(x) = 4x + 5. Show that f is invertible and find f–1. - Mathematics

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प्रश्न

Let R be the set of real numbers and f: R → R be the function defined by f(x) = 4x + 5. Show that f is invertible and find f–1.

बेरीज
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उत्तर

Here the function f : R → R is defined as f (x) = 4x + 5 = y (say). Then

4x = y – 5 or x = `(y - 5)/4`.

This leads to a function g: R → R defined as

g(y) = `(y - 5)/4`.

Therefore, (gof) (x) = g(f(x) = g(4x + 5)

= `(4x + 5 - 5)/4`

= x

or

gof = IR

Similarly (fog) (y) = f(g(y))

= `f((y - 5)/4)`

= `4((y - 5)/4) + 5`

= y

or

fog = IR

Hence f is invertible and f-1 = g which is given by `f^-1 (x) = (x - 5)/4`

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पाठ 1: Relations And Functions - Solved Examples [पृष्ठ ६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 1 Relations And Functions
Solved Examples | Q 15 | पृष्ठ ६

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