मराठी

Integrate the function 18+3x -x2

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प्रश्न

Integrate the function `1/sqrt(8+3x  - x^2)`

बेरीज
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उत्तर

Let `I = int 1/sqrt(8 + 3x - x^2)  dx`

`= int dx/sqrt(8 - (x^2 - 3x))`

`= int dx/sqrt(8 - (x^2 - 2 * 3/2 x + 9/4) + 9/4)`

`= int dx/sqrt(41/4 - (x - 3/2)^2)`

`= int dx/sqrt((sqrt41/2)^2 - (x - 3/2)^2)`          `...[∵ int dx/sqrt (a^2 - x^2) = sin^-1  x/a + C]`

`= sin^-1 ((x - 3/2)/(sqrt41/2)) + C`

`= sin^-1 ((2x - 3)/sqrt41) + C`

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पाठ 7: Integrals - Exercise 7.4 [पृष्ठ ३१६]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.4 | Q 14 | पृष्ठ ३१६

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